modf, modff, modfl
Header: <math.h>
1-3) Decomposes given floating-point value arg into integral and fractional parts, each having the same type and sign as arg. The integral part (in floating-point format) is stored in the object pointed to by iptr.
# Declarations
float modff( float arg, float* iptr );
(since C99)
double modf( double arg, double* iptr );
long double modfl( long double arg, long double* iptr );
(since C99)
# Parameters
arg: floating-point valueiptr: pointer to floating-point value to store the integral part to
# Return value
If no errors occur, returns the fractional part of arg with the same sign as arg. The integral part is put into the value pointed to by iptr.
# Notes
This function behaves as if implemented as follows:
# Example
#include <float.h>
#include <math.h>
#include <stdio.h>
int main(void)
{
double f = 123.45;
printf("Given the number %.2f or %a in hex,\n", f, f);
double f3;
double f2 = modf(f, &f3);
printf("modf() makes %.2f + %.2f\n", f3, f2);
int i;
f2 = frexp(f, &i);
printf("frexp() makes %f * 2^%d\n", f2, i);
i = ilogb(f);
printf("logb()/ilogb() make %f * %d^%d\n", f / scalbn(1.0, i), FLT_RADIX, i);
// special values
f2 = modf(-0.0, &f3);
printf("modf(-0) makes %.2f + %.2f\n", f3, f2);
f2 = modf(-INFINITY, &f3);
printf("modf(-Inf) makes %.2f + %.2f\n", f3, f2);
}