std::copy_n
Min standard notice:
Header: <algorithm>
- Copies exactly count values from the range beginning at first to the range beginning at result. Formally, for each integer i in [0,count), performs *(result + i) = *(first + i).
# Declarations
template< class InputIt, class Size, class OutputIt >
OutputIt copy_n( InputIt first, Size count, OutputIt result );
(since C++11) (constexpr since C++20)
template< class ExecutionPolicy,
class ForwardIt1, class Size, class ForwardIt2 >
ForwardIt2 copy_n( ExecutionPolicy&& policy,
ForwardIt1 first, Size count, ForwardIt2 result );
(since C++17)
# Parameters
first: the beginning of the range of elements to copy fromcount: number of the elements to copyresult: the beginning of the destination rangepolicy: the execution policy to use
# Return value
Iterator in the destination range, pointing past the last element copied if count > 0 or result otherwise.
# Example
#include <algorithm>
#include <iostream>
#include <iterator>
#include <numeric>
#include <string>
#include <vector>
int main()
{
std::string in {"1234567890"};
std::string out;
std::copy_n(in.begin(), 4, std::back_inserter(out));
std::cout << out << '\n';
std::vector<int> v_in(128);
std::iota(v_in.begin(), v_in.end(), 1);
std::vector<int> v_out(v_in.size());
std::copy_n(v_in.cbegin(), 100, v_out.begin());
std::cout << std::accumulate(v_out.begin(), v_out.end(), 0) << '\n';
}