std::equal_range
Header: <algorithm>
Returns a range containing all elements equivalent to value in the partitioned range [first,last).
# Declarations
template< class ForwardIt, class T >
std::pair<ForwardIt, ForwardIt>
equal_range( ForwardIt first, ForwardIt last, const T& value );
(constexpr since C++20) (until C++26)
template< class ForwardIt, class T = typename std::iterator_traits
<ForwardIt>::value_type >
constexpr std::pair<ForwardIt, ForwardIt>
equal_range( ForwardIt first, ForwardIt last, const T& value );
(since C++26)
template< class ForwardIt, class T, class Compare >
std::pair<ForwardIt, ForwardIt>
equal_range( ForwardIt first, ForwardIt last,
const T& value, Compare comp );
(constexpr since C++20) (until C++26)
template< class ForwardIt, class T = typename std::iterator_traits
<ForwardIt>::value_type,
class Compare >
constexpr std::pair<ForwardIt, ForwardIt>
equal_range( ForwardIt first, ForwardIt last,
const T& value, Compare comp );
(since C++26)
# Parameters
first, last: the partitioned range of elements to examinevalue: value to compare the elements tocomp: binary predicate which returns true if the first argument is ordered before the second. The signature of the predicate function should be equivalent to the following: bool pred(const Type1 &a, const Type2 &b); While the signature does not need to have const &, the function must not modify the objects passed to it and must be able to accept all values of type (possibly const) Type1 and Type2 regardless of value category (thus, Type1 & is not allowed, nor is Type1 unless for Type1 a move is equivalent to a copy(since C++11)). The types Type1 and Type2 must be such that an object of type T can be implicitly converted to both Type1 and Type2, and an object of type ForwardIt can be dereferenced and then implicitly converted to both Type1 and Type2.
# Return value
A std::pair containing a pair of iterators, where
# Notes
Although std::equal_range only requires [first,last) to be partitioned, this algorithm is usually used in the case where [first,last) is sorted, so that the binary search is valid for any value.
On top of the requirements of std::lower_bound and std::upper_bound, std::equal_range also requires operator< or comp to be asymmetric (i.e., a < b and b < a always have different results).
Therefore, the intermediate results of binary search can be shared by std::lower_bound and std::upper_bound. For example, the result of the std::lower_bound call can be used as the argument of first in the std::upper_bound call.
# Example
#include <algorithm>
#include <complex>
#include <iostream>
#include <vector>
struct S
{
int number;
char name;
// note: name is ignored by this comparison operator
bool operator<(const S& s) const { return number < s.number; }
};
struct Comp
{
bool operator()(const S& s, int i) const { return s.number < i; }
bool operator()(int i, const S& s) const { return i < s.number; }
};
int main()
{
// note: not ordered, only partitioned w.r.t. S defined below
const std::vector<S> vec{{1, 'A'}, {2, 'B'}, {2, 'C'},
{2, 'D'}, {4, 'G'}, {3, 'F'}};
const S value{2, '?'};
std::cout << "Compare using S::operator<(): ";
const auto p = std::equal_range(vec.begin(), vec.end(), value);
for (auto it = p.first; it != p.second; ++it)
std::cout << it->name << ' ';
std::cout << '\n';
std::cout << "Using heterogeneous comparison: ";
const auto p2 = std::equal_range(vec.begin(), vec.end(), 2, Comp{});
for (auto it = p2.first; it != p2.second; ++it)
std::cout << it->name << ' ';
std::cout << '\n';
using CD = std::complex<double>;
std::vector<CD> nums{{1, 0}, {2, 2}, {2, 1}, {3, 0}, {3, 1}};
auto cmpz = [](CD x, CD y) { return x.real() < y.real(); };
#ifdef __cpp_lib_algorithm_default_value_type
auto p3 = std::equal_range(nums.cbegin(), nums.cend(), {2, 0}, cmpz);
#else
auto p3 = std::equal_range(nums.cbegin(), nums.cend(), CD{2, 0}, cmpz);
#endif
for (auto it = p3.first; it != p3.second; ++it)
std::cout << *it << ' ';
std::cout << '\n';
}
# Defect reports
| DR | Applied to | Behavior as published | Correct behavior |
|---|---|---|---|
| LWG 270 | C++98 | Compare was required to satisfy Compare and T was requiredto be LessThanComparable (strict weak ordering required) | only a partitioning is required;heterogeneous comparisons permitted |
| LWG 384 | C++98 | at most (\scriptsize 2\log_{2}(N)+1)2log2(N)+1 comparisonswere allowed, which is not implementable[1] | corrected to (\scriptsize 2\log_{2}(N)+O(1))2log2(N)+O(1) |