std::chrono::year::operator+=, std::chrono::year::operator-=
Min standard notice:
Adds or subtracts y.count() years from the year value.
# Declarations
constexpr std::chrono::year& operator+=( const std::chrono::years& y ) noexcept;
(since C++20)
constexpr std::chrono::year& operator-=( const std::chrono::years& y ) noexcept;
(since C++20)
# Return value
A reference to this year after modification.
# Notes
If the result would be outside the range [-32767,32767], the actual stored value is unspecified.
# Example
#include <chrono>
#include <iostream>
int main()
{
using namespace std::literals::chrono_literals;
std::cout << std::boolalpha;
std::chrono::year y{2020};
y += std::chrono::years(12);
std::cout << (y == 2032y) << ' ';
y -= std::chrono::years(33);
std::cout << (y == 1999y) << '\n';
}