std::chrono::year_month_day::operator sys_days, std::chrono::year_month_day::operator local_days

Since C++20

Converts *this to a std::chrono::time_point representing the same date as this year_month_day.

# Declarations

constexpr operator std::chrono::sys_days() const noexcept;

(since C++20)

constexpr explicit operator std::chrono::local_days() const noexcept;

(since C++20)

# Notes

Converting to std::chrono::sys_days and back can be used to normalize a year_month_day that contains an invalid day but a valid year and month:

Normalizing the year and month can be done by adding (or subtracting) zero std::chrono::months:

# Example

#include <chrono>
#include <iostream>
 
int main()
{
    using namespace std::chrono;
    const auto today = sys_days{std::chrono::floor<days>(system_clock::now())};
    for (const year_month_day ymd : {{November/15/2020}, {November/15/2120}, today})
    {
        std::cout << ymd;
        const auto delta = (sys_days{ymd} - today).count();
        (delta < 0) ? std::cout << " was " << -delta << " day(s) ago\n" :
        (delta > 0) ? std::cout << " is " << delta << " day(s) from now\n"
                    : std::cout << " is today!\n";
    }
}