std::deque<T,Allocator>::operator=

Since C++17

Replaces the contents of the container.

# Declarations

deque& operator=( const deque& other );

deque& operator=( deque&& other );

(since C++11) (until C++17)

deque& operator=( deque&& other ) noexcept(/* see below */);

(since C++17)

deque& operator=( std::initializer_list<value_type> ilist );

(since C++11)

# Parameters

# Return value

*this

# Notes

After container move assignment (overload (2)), unless element-wise move assignment is forced by incompatible allocators, references, pointers, and iterators (other than the end iterator) to other remain valid, but refer to elements that are now in *this. The current standard makes this guarantee via the blanket statement in [container.reqmts]/67, and a more direct guarantee is under consideration via LWG issue 2321.

# Example

#include <initializer_list>
#include <iostream>
#include <iterator>
#include <deque>
 
void print(auto const comment, auto const& container)
{
    auto size = std::size(container);
    std::cout << comment << "{ ";
    for (auto const& element : container)
        std::cout << element << (--size ? ", " : " ");
    std::cout << "}\n";
}
 
int main()
{
    std::deque<int> x{1, 2, 3}, y, z;
    const auto w = {4, 5, 6, 7};
 
    std::cout << "Initially:\n";
    print("x = ", x);
    print("y = ", y);
    print("z = ", z);
 
    std::cout << "Copy assignment copies data from x to y:\n";
    y = x;
    print("x = ", x);
    print("y = ", y);
 
    std::cout << "Move assignment moves data from x to z, modifying both x and z:\n";
    z = std::move(x);
    print("x = ", x);
    print("z = ", z);
 
    std::cout << "Assignment of initializer_list w to z:\n";
    z = w;
    print("w = ", w);
    print("z = ", z);
}

# See also