std::shared_ptr<T>::owner_before

Checks whether this shared_ptr precedes other in implementation defined owner-based (as opposed to value-based) order. The order is such that two smart pointers compare equivalent only if they are both empty or if they both own the same object, even if the values of the pointers obtained by get() are different (e.g. because they point at different subobjects within the same object).

# Declarations

template< class Y >
bool owner_before( const shared_ptr<Y>& other ) const noexcept;
template< class Y >
bool owner_before( const std::weak_ptr<Y>& other ) const noexcept;

# Parameters

# Return value

true if *this precedes other, false otherwise. Common implementations compare the addresses of the control blocks.

# Example

#include <iostream>
#include <memory>
 
struct Foo
{
    int n1;
    int n2; 
    Foo(int a, int b) : n1(a), n2(b) {}
};
 
int main()
{   
    auto p1 = std::make_shared<Foo>(1, 2);
    std::shared_ptr<int> p2(p1, &p1->n1);
    std::shared_ptr<int> p3(p1, &p1->n2);
 
    std::cout << std::boolalpha
              << "p2 < p3 " << (p2 < p3) << '\n'
              << "p3 < p2 " << (p3 < p2) << '\n'
              << "p2.owner_before(p3) " << p2.owner_before(p3) << '\n'
              << "p3.owner_before(p2) " << p3.owner_before(p2) << '\n';
 
    std::weak_ptr<int> w2(p2);
    std::weak_ptr<int> w3(p3);
    std::cout 
//            << "w2 < w3 " << (w2 < w3) << '\n' // won't compile 
//            << "w3 < w2 " << (w3 < w2) << '\n' // won't compile
              << "w2.owner_before(w3) " << w2.owner_before(w3) << '\n'
              << "w3.owner_before(w2) " << w3.owner_before(w2) << '\n';
}

# Defect reports

DRApplied toBehavior as publishedCorrect behavior
LWG 2873C++11owner_before was not declared noexceptdeclared noexcept

# See also