std::begin(std::valarray)

The overload of std::begin for valarray returns an iterator of unspecified type referring to the first element in the numeric array.

# Declarations

template< class T >
/* see below */ begin( valarray<T>& v );

(since C++11)

template< class T >
/* see below */ begin( const valarray<T>& v );

(since C++11)

# Parameters

# Return value

Iterator to the first value in the numeric array.

# Notes

Unlike other functions that take std::valarray arguments, begin() cannot accept the replacement types (such as the types produced by expression templates) that may be returned from expressions involving valarrays: std::begin(v1 + v2) is not portable, std::begin(std::valarray(v1 + v2)) has to be used instead.

The intent of this function is to allow range for loops to work with valarrays, not to provide container semantics.

# Example

#include <algorithm>
#include <iostream>
#include <valarray>
 
void show(const std::valarray<int>& v)
{
    std::for_each(std::begin(v), std::end(v), [](int c)
    {
        std::cout << c << ' ';
    });
    std::cout << '\n';
};
 
int main()
{
    const std::valarray<int> x{47, 70, 37, 52, 90, 23, 17, 33, 22, 16, 21, 4};
    const std::valarray<int> y{25, 31, 71, 56, 21, 21, 15, 34, 21, 27, 12, 6};
 
    show(x); 
    show(y); 
 
    const std::valarray<int> z{x + y};
 
    for (char c : z)
        std::cout << c;
}

# Defect reports

DRApplied toBehavior as publishedCorrect behavior
LWG 2058C++111. begin() was required to support replacement types2. it was unspecified when the returned iterators will be invalidated1. not required2. specified

# See also