std::numeric_limits<T>::is_specialized

Since C++11

The value of std::numeric_limits::is_specialized is true for all T for which there exists a specialization of std::numeric_limits.

# Declarations

static const bool is_specialized;

(until C++11)

static constexpr bool is_specialized;

(since C++11)

# Example

#include <iostream>
#include <limits>
#include <type_traits>
 
int main()
{
    enum E{};
 
    std::cout << std::boolalpha
              << std::numeric_limits<bool>::is_specialized << '\n'
              << std::numeric_limits<long long>::is_specialized << '\n'
              << std::numeric_limits<std::true_type>::is_specialized << '\n'
              << std::numeric_limits<E>::is_specialized << '\n';
}

# See also