std::numeric_limits<T>::max_digits10
Min standard notice:
The value of std::numeric_limits
# Declarations
static constexpr int max_digits10
(since C++11)
# Notes
Unlike most mathematical operations, the conversion of a floating-point value to text and back is exact as long as at least max_digits10 were used (9 for float, 17 for double): it is guaranteed to produce the same floating-point value, even though the intermediate text representation is not exact. It may take over a hundred decimal digits to represent the precise value of a float in decimal notation.
# Example
#include <cmath>
#include <iomanip>
#include <iostream>
#include <limits>
#include <sstream>
int main()
{
float value = 10.0000086;
constexpr auto digits10 = std::numeric_limits<decltype(value)>::digits10;
constexpr auto max_digits10 = std::numeric_limits<decltype(value)>::max_digits10;
constexpr auto submax_digits10 = max_digits10 - 1;
std::cout << "float:\n"
" digits10 is " << digits10 << " digits\n"
" max_digits10 is " << max_digits10 << " digits\n"
"submax_digits10 is " << submax_digits10 << " digits\n\n";
const auto original_precision = std::cout.precision();
for (auto i = 0; i < 5; ++i)
{
std::cout
<< " max_digits10: " << std::setprecision(max_digits10) << value << "\n"
"submax_digits10: " << std::setprecision(submax_digits10) << value
<< "\n\n";
value = std::nextafter(value, std::numeric_limits<decltype(value)>::max());
}
std::cout.precision(original_precision);
}