std::make_any
Min standard notice:
Header: <any>
Constructs an any object containing an object of type T, passing the provided arguments to T’s constructor.
# Declarations
template< class T, class... Args >
std::any make_any( Args&&... args );
(since C++17)
template< class T, class U, class... Args >
std::any make_any( std::initializer_list<U> il, Args&&... args );
(since C++17)
# Example
#include <any>
#include <complex>
#include <functional>
#include <iostream>
#include <string>
int main()
{
auto a0 = std::make_any<std::string>("Hello, std::any!\n");
auto a1 = std::make_any<std::complex<double>>(0.1, 2.3);
std::cout << std::any_cast<std::string&>(a0);
std::cout << std::any_cast<std::complex<double>&>(a1) << '\n';
using lambda = std::function<void(void)>;
// Put a lambda into std::any. Attempt #1 (failed).
std::any a2 = [] { std::cout << "Lambda #1.\n"; };
std::cout << "a2.type() = \"" << a2.type().name() << "\"\n";
// any_cast casts to <void(void)> but actual type is not
// a std::function..., but ~ main::{lambda()#1}, and it is
// unique for each lambda. So, this throws...
try
{
std::any_cast<lambda>(a2)();
}
catch (std::bad_any_cast const& ex)
{
std::cout << ex.what() << '\n';
}
// Put a lambda into std::any. Attempt #2 (successful).
auto a3 = std::make_any<lambda>([] { std::cout << "Lambda #2.\n"; });
std::cout << "a3.type() = \"" << a3.type().name() << "\"\n";
std::any_cast<lambda>(a3)();
}