std::optional<T>::transform
Min standard notice:
If *this contains a value, invokes f with the contained value as an argument, and returns an std::optional that contains the result of that invocation; otherwise, returns an empty std::optional.
# Declarations
template< class F >
constexpr auto transform( F&& f ) &;
(since C++23)
template< class F >
constexpr auto transform( F&& f ) const&;
(since C++23)
template< class F >
constexpr auto transform( F&& f ) &&;
(since C++23)
template< class F >
constexpr auto transform( F&& f ) const&&;
(since C++23)
# Parameters
f: a suitable function or Callable object whose call signature returns a non-reference type
# Return value
An std::optional containing the result of f or an empty std::optional, as described above.
# Notes
Because transform directly constructs a U object at the right location, rather than passing it to a constructor, std::is_move_constructible_v can be false.
As the callable f can’t return a reference type, it cannot be a pointer to data member.
Some languages call this operation map.
# Example
#include <iostream>
#include <optional>
struct A { /* ... */ };
struct B { /* ... */ };
struct C { /* ... */ };
struct D { /* ... */ };
auto A_to_B(A) -> B { /* ... */ std::cout << "A => B \n"; return {}; }
auto B_to_C(B) -> C { /* ... */ std::cout << "B => C \n"; return {}; }
auto C_to_D(C) -> D { /* ... */ std::cout << "C => D \n"; return {}; }
void try_transform_A_to_D(std::optional<A> o_A)
{
std::cout << (o_A ? "o_A has a value\n" : "o_A is empty\n");
std::optional<D> o_D = o_A.transform(A_to_B)
.transform(B_to_C)
.transform(C_to_D);
std::cout << (o_D ? "o_D has a value\n\n" : "o_D is empty\n\n");
};
int main()
{
try_transform_A_to_D( A{} );
try_transform_A_to_D( {} );
}